document.write( "Question 278185: write an equationfor the line that is perpendicular to the given line and that passes through the given point
\n" ); document.write( "y=x-3;(4,6) and\r
\n" ); document.write( "\n" ); document.write( "find the slope of a line perpendicular to the graph of each equation y=-3x
\n" ); document.write( "

Algebra.Com's Answer #202433 by subbbu(3)\"\" \"About 
You can put this solution on YOUR website!
passes through the given point
\n" ); document.write( "y=x-3;(4,6) and\r
\n" ); document.write( "\n" ); document.write( "slope of any line perpendicular to a given line of slope m =-1/m since their slopes product must be equal to -1.
\n" ); document.write( "y =x-3.
\n" ); document.write( "slope m =1.
\n" ); document.write( "slope a kine perpenducolr to this line =-1/1 =-1.
\n" ); document.write( "(4,6)
\n" ); document.write( "y-y1=m(x-x1)
\n" ); document.write( "y-6= -1(x-4)
\n" ); document.write( "y-6== -x+4
\n" ); document.write( "y+x-10 =0.
\n" ); document.write( "find the slope of a line perpendicular to the graph of each equation y=-3x
\n" ); document.write( "slopof y =-3x m =-3.
\n" ); document.write( "as said above slope of a line perpendiculr to y =-63x is -1/-3 =1/3.
\n" ); document.write( "
\n" );