document.write( "Question 278185: write an equationfor the line that is perpendicular to the given line and that passes through the given point
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document.write( "y=x-3;(4,6) and\r
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document.write( "find the slope of a line perpendicular to the graph of each equation y=-3x \n" );
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Algebra.Com's Answer #202433 by subbbu(3)![]() ![]() ![]() You can put this solution on YOUR website! passes through the given point \n" ); document.write( "y=x-3;(4,6) and\r \n" ); document.write( "\n" ); document.write( "slope of any line perpendicular to a given line of slope m =-1/m since their slopes product must be equal to -1. \n" ); document.write( "y =x-3. \n" ); document.write( "slope m =1. \n" ); document.write( "slope a kine perpenducolr to this line =-1/1 =-1. \n" ); document.write( "(4,6) \n" ); document.write( "y-y1=m(x-x1) \n" ); document.write( "y-6= -1(x-4) \n" ); document.write( "y-6== -x+4 \n" ); document.write( "y+x-10 =0. \n" ); document.write( "find the slope of a line perpendicular to the graph of each equation y=-3x \n" ); document.write( "slopof y =-3x m =-3. \n" ); document.write( "as said above slope of a line perpendiculr to y =-63x is -1/-3 =1/3. \n" ); document.write( " |