document.write( "Question 278163: A triangular piece of glass is being cut so that the height of the triangle is 4 inches shorter than twice the base. If the area of the triangle is 80 square inches, how long is the height of the triangle? \n" ); document.write( "
Algebra.Com's Answer #202423 by checkley77(12844) ![]() You can put this solution on YOUR website! Area=bh/2 \n" ); document.write( "80=b(2b-4)/2 \n" ); document.write( "80=(2b^2-4b)/2 cross multiply \n" ); document.write( "2b^2-4b=2*80 \n" ); document.write( "2b^2-4b=160 \n" ); document.write( "2b^2-4b-160=0 \n" ); document.write( "2(b^2-2b-80)=0 \n" ); document.write( "2(b-10)(b+8)=0 \n" ); document.write( "b-10=0 \n" ); document.write( "b=10 in. \n" ); document.write( "h=2*10-4 \n" ); document.write( "h=20-4 \n" ); document.write( "h=16 in. \n" ); document.write( "Proof: \n" ); document.write( "80=10(2*10-4)/2 \n" ); document.write( "80=10(20-4)/2 \n" ); document.write( "80=10*16/2 \n" ); document.write( "80=160/2 \n" ); document.write( "80=80 \n" ); document.write( " |