document.write( "Question 278163: A triangular piece of glass is being cut so that the height of the triangle is 4 inches shorter than twice the base. If the area of the triangle is 80 square inches, how long is the height of the triangle? \n" ); document.write( "
Algebra.Com's Answer #202423 by checkley77(12844)\"\" \"About 
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Area=bh/2
\n" ); document.write( "80=b(2b-4)/2
\n" ); document.write( "80=(2b^2-4b)/2 cross multiply
\n" ); document.write( "2b^2-4b=2*80
\n" ); document.write( "2b^2-4b=160
\n" ); document.write( "2b^2-4b-160=0
\n" ); document.write( "2(b^2-2b-80)=0
\n" ); document.write( "2(b-10)(b+8)=0
\n" ); document.write( "b-10=0
\n" ); document.write( "b=10 in.
\n" ); document.write( "h=2*10-4
\n" ); document.write( "h=20-4
\n" ); document.write( "h=16 in.
\n" ); document.write( "Proof:
\n" ); document.write( "80=10(2*10-4)/2
\n" ); document.write( "80=10(20-4)/2
\n" ); document.write( "80=10*16/2
\n" ); document.write( "80=160/2
\n" ); document.write( "80=80
\n" ); document.write( "
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