document.write( "Question 278057: Two cards are drawn without replacement from an ordinary deck of 52 playing cards. What are the odds against drawing a club and a diamond? \r
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\n" ); document.write( "\n" ); document.write( "What are the odds against getting all heads or all tails in three successive flips of a coin?
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Algebra.Com's Answer #202376 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
Two cards are drawn without replacement from an ordinary deck of 52 playing cards. What are the odds against drawing a club and a diamond?
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\n" ); document.write( "To get the odds against you need the probability for and the probability
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\n" ); document.write( "P(club and diamond) = (13/52)(13/51)
\n" ); document.write( "P(not drawing a club and a diamond) = 1 - (13^2/(52*51)) = (52*51-13^2)/(52*51)
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\n" ); document.write( "Then odds against = P(against)/P(for) = (52*51-13^2)/13^2 = 2483:169
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\n" ); document.write( "\n" ); document.write( "What are the odds against getting all heads or all tails in three successive flips of a coin?
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\n" ); document.write( "P(all heads) = 1/8
\n" ); document.write( "P(all tails) = 1/8
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\n" ); document.write( "Assuming these events are independent you get:
\n" ); document.write( "P(all heads and all tails) = (1/8)^2 = 1/64
\n" ); document.write( "P(not) = 1-(1/64) = 63/64
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\n" ); document.write( "Then odd against = P(not)/P(for) = 63/1 = 63:1
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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