document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=278007>Question 278007</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Hi! I need some help with this 2 qestions<BR>\n" );
document.write( "1.if the angle is 60 less than twice its complement,find the ratio of the angle to its complement.<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #202351 by </B><A HREF=/tutors/aboutme.mpl?userid=richwmiller><B>richwmiller(17219)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=richwmiller><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=richwmiller><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=202351\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Sorry one problem per submission and no similar problems.<BR>\n" );
document.write( "the key to your problems is knowing that complementary angles add up to 90 degrees.<BR>\n" );
document.write( "a=2c-60<BR>\n" );
document.write( "a+c=90<BR>\n" );
document.write( "2c-60+c=90<BR>\n" );
document.write( "3c=150<BR>\n" );
document.write( "c=50<BR>\n" );
document.write( "a=40<BR>\n" );
document.write( "angle is 40<BR>\n" );
document.write( "40/50=4/5 ratio <BR>\n" );
document.write( "check<BR>\n" );
document.write( "2*50-60=40<BR>\n" );
document.write( "100-60=40<BR>\n" );
document.write( "40=40<BR>\n" );
document.write( "ok </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );