document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=32054>Question 32054</A>: <I><SPAN STYLE=\"word-break: break-all;\"> (2/(x+4)) - (3/(x-1))>=0\r<BR>\n" );
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document.write( "Is the answer (-4,1)?<BR>\n" );
document.write( "Thank you,<BR>\n" );
document.write( "Alexus </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #20235 by </B><A HREF=/tutors/aboutme.mpl?userid=Prithwis><B>Prithwis(166)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Prithwis><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.nriassociation.com/BeliveITorNOT/mittal70millionHouse.jpg valign=middle><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=20235\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> (2/(x+4)) - (3/(x-1))>=0<BR>\n" );
document.write( "=> [2(x-1) - 3(x+4) ]/(x+4)(x-1) >= 0<BR>\n" );
document.write( "=> [-x-14]/(x+4)(x-1) >= 0 .........(1)<BR>\n" );
document.write( "It seems you are looking for intervals.<BR>\n" );
document.write( "The Boundary points are x=-4, x=1, x = 14<BR>\n" );
document.write( "For x< -14, (1) is positive<BR>\n" );
document.write( "For x in (-14, -4), (1) is negative<BR>\n" );
document.write( "For x in (-4,1), (1) is positive<BR>\n" );
document.write( "For x > 1, (1) is negative<BR>\n" );
document.write( "The answer would be x belongs to (-infinity, -14] U (-4, 1)<BR>\n" );
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