document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=277867>Question 277867</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Could you please show me the steps to solve sin 2 y = cos 4 y for y, where 0 degrees = y or < y < 360 degrees. I'm constantly messing up big time somewhere hopefully steps will help. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #202279 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=202279\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\">  sin 2y = cos4 y for y, where 0 degrees = y or < y < 360 degrees<BR>\n" );
document.write( "-------------<BR>\n" );
document.write( "sin(2y) = cos^2(2y) - sin^2(2y)<BR>\n" );
document.write( "sin(2y) = 1-sin^2(2y) - sin^2(2y) = 1 - 2sin^2(2y)<BR>\n" );
document.write( "2sin^2(2y) + sin(2y) - 1 = 0 a quadratic in sin(2y)<BR>\n" );
document.write( "(2sin + 1)*(sin - 1) = 0<BR>\n" );
document.write( "sin(2y) = -1/2<BR>\n" );
document.write( "sin(2y) = 1<BR>\n" );
document.write( "---------------<BR>\n" );
document.write( "sin(2y) = 1<BR>\n" );
document.write( "2y = 90, 450<BR>\n" );
document.write( "y = 45, 225<BR>\n" );
document.write( "--------------<BR>\n" );
document.write( "sin(2y) = -1/2<BR>\n" );
document.write( "2y = 210, 330, 570, 690<BR>\n" );
document.write( "y = 105, 165, 285, 345<BR>\n" );
document.write( "All y values in degrees\r<BR>\n" );
document.write( "\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );