document.write( "Question 277732: Chuck and Dana agree to meet in Chicago for the weekend. Chuck travels 160 miles in the same time that Dana travels 145 miles. If Chuck's rate of travel is 3 mph more than Dana's, and they travel the same length of time, at what speed does Chuck travel? \n" ); document.write( "
Algebra.Com's Answer #202266 by checkley77(12844)![]() ![]() ![]() You can put this solution on YOUR website! D=RT \n" ); document.write( "160=(R+3)T \n" ); document.write( "T=160/(R+3) \n" ); document.write( "145=RT \n" ); document.write( "T=145/R \n" ); document.write( "SEEING AS THE TIMES ARE THE SAME: \n" ); document.write( "160/(R+3)=145/R CROSS MULTIPLY. \n" ); document.write( "160R=145(R+3) \n" ); document.write( "160R=145R+435 \n" ); document.write( "160R-145R=435 \n" ); document.write( "15R=435 \n" ); document.write( "R=435/15 \n" ); document.write( "R=29 MPH FOR DANA'S RATE. \n" ); document.write( "29+3=32 MPH FOR CHUCK'S RATE. \n" ); document.write( "PROOF: \n" ); document.write( "160/32=145/29 \n" ); document.write( "5=5 \n" ); document.write( " \n" ); document.write( " |