document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=277812>Question 277812</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Solution A is 25% acid and solution B is 40% acid. How much of each solution is needed to make 100 liters of 30% acid? <BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #202214 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=202214\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Solution A is 25% acid and solution B is 40% acid. How much of each solution is needed to make 100 liters of 30% acid? <BR>\n" );
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document.write( "One variable solution:<BR>\n" );
document.write( "0.25x + 0.40(100-x) = 0.30*100<BR>\n" );
document.write( "Multiply thru by 100 to get:<BR>\n" );
document.write( "25x + 40*100 - 40x = 30*100<BR>\n" );
document.write( "-15x = -10*100<BR>\n" );
document.write( "x = (2/3)100<BR>\n" );
document.write( "x = 66.67 liters (amt of 25% solution needed in the mixture)<BR>\n" );
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document.write( "100-x = 33.3 liters (amt of 40% solution needed in the mixture)<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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