document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=277770>Question 277770</A>: <I><SPAN STYLE=\"word-break: break-all;\">  A triangle has a perimeter of 105 inches. The lengths of the sides of the triangle are consecutive odd integers. Find the length of the sides and then use Heron’s Formula to find the area of a triangle. Show all work to receive credit </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #202181 by </B><A HREF=/tutors/aboutme.mpl?userid=richwmiller><B>richwmiller(17219)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=richwmiller><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=richwmiller><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=202181\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> n+n+2+n+4=105<BR>\n" );
document.write( "3n+6=105<BR>\n" );
document.write( "3n=99<BR>\n" );
document.write( "n=33<BR>\n" );
document.write( "A=sqrt(s*(s-a)*(s-b)*(s-c))<BR>\n" );
document.write( "where s=105/2=52.5<BR>\n" );
document.write( "A=sqrt(52.5*(52.5-33)*(52.5-35)*(52.5-37))<BR>\n" );
document.write( "A=526.965 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );