document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=277762>Question 277762</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I need help on this new form of equation that we're learning in school that I still don't understand. It evidently has something to do with parabolas. Here's the problem:\r<BR>\n" );
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document.write( "In firefighting, a good water stream can be modeled by:\r<BR>\n" );
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document.write( "y=-0.003x^2 + 0.62x + 3\r<BR>\n" );
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document.write( "where x is the water's horizontal distance traveled (in feet) and y is its corresponding height (in feet). If a firefighter is aiming a good water stream at a building's window 25 feet above the ground, at what two distances can the firefighter stand from the building?\r<BR>\n" );
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document.write( "Please help me. I have no idea where to even start.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #202177 by </B><A HREF=/tutors/aboutme.mpl?userid=richwmiller><B>richwmiller(17219)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=richwmiller><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=richwmiller><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=202177\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 25 will be y the height<BR>\n" );
document.write( "so plug in 25 for y and find x<BR>\n" );
document.write( "(x-161.165) (x-45.5022) = 0 </SPAN>\n" );
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