document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=277701>Question 277701</A>: <I><SPAN STYLE=\"word-break: break-all;\"> if the first and third of three consecutive odd integers are added, the result is 87 less than five times the second interger. find the third interger </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #202175 by </B><A HREF=/tutors/aboutme.mpl?userid=MathTherapy><B>MathTherapy(10552)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=MathTherapy><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=MathTherapy><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=202175\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let the 1st integer be F\r<BR>\n" );
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document.write( "Then the 2nd and 3rd integers are F + 2 and F + 4, respectively\r<BR>\n" );
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document.write( "Sum of 1st and 3rd integers = F + F + 4, or 2F + 4\r<BR>\n" );
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document.write( "Therefore, 2F +  4 = 5(F + 2) – 87\r<BR>\n" );
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document.write( "2F + 4 = 5F + 10 – 87\r<BR>\n" );
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document.write( "2F - 5F = - 4 + 10 – 87\r<BR>\n" );
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document.write( "-3F = - 81\r<BR>\n" );
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document.write( "F = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%28-81%29%2F%28-3%29 ALIGN=MIDDLE  ALT=\"%28-81%29%2F%28-3%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > = 27\r<BR>\n" );
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document.write( "Since the 1st integer, or F equals 27, then the 3rd integer is <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=highlight_green%2831%29 ALIGN=MIDDLE  ALT=\"highlight_green%2831%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >(F + 4) = 27 + 4<BR>\n" );
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