document.write( "Question 277166: find the value of a, b, and c so that i can decompose it to partial functions\r
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document.write( "(3x -13)/(6x^2-x-12)\r
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document.write( "thank you! \n" );
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Algebra.Com's Answer #202126 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! find the value of a, b, and c so that i can decompose it to partial functions \n" ); document.write( " \n" ); document.write( ": \n" ); document.write( "Write the given expression as a sum using A & B \n" ); document.write( " \n" ); document.write( ": \n" ); document.write( "Multiply by the LCD, (2x-3)(3x+4) \n" ); document.write( "(2x-3)(3x+4) \n" ); document.write( "results \n" ); document.write( "3x - 13 = A(3x+4) + B(2x-3) \n" ); document.write( ": \n" ); document.write( "3x - 13 = 3xA + 4A + 2xB - 3B \n" ); document.write( ": \n" ); document.write( "3x - 13 - (3A + 2B)x + 4A - 3B \n" ); document.write( "Coefficients of x are equal \n" ); document.write( "3A + 2B = 3 \n" ); document.write( "Constants are equal \n" ); document.write( "4A - 3B = -13 \n" ); document.write( "; \n" ); document.write( "Solve for two unknowns using elimination, multiply 1st eq by 3, 2nd eq by 2 \n" ); document.write( "9A + 6B = 9 \n" ); document.write( "8A - 6B =-26 \n" ); document.write( "----------------adding eliminates B, find A \n" ); document.write( "17A = -17 \n" ); document.write( "A = -1 \n" ); document.write( ": \n" ); document.write( "Find B \n" ); document.write( "3A + 2B = 3 \n" ); document.write( "3(-1) + 2B = 3 \n" ); document.write( "-3 + 2B = 3 \n" ); document.write( "2B = 3 + 3 \n" ); document.write( "2B = 6 \n" ); document.write( "B = 3 \n" ); document.write( ": \n" ); document.write( "We have \n" ); document.write( " \n" ); document.write( ": \n" ); document.write( "You should check this by adding the two fractions on the right to see if they equal the expression on the left \n" ); document.write( " \n" ); document.write( " |