document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=277656>Question 277656</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I have searched everywhere reading everything... I do not know how to turn this problem into a quadratic equation. Sammy takes 5 hours longer to complete 300 lines of code than Martin. Together Sammy and Martin can complete the code in 6 hours. How long does it take each programmer to complete the code if they complete on their own. At what speed is each programming lines per hour </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #202120 by </B><A HREF=/tutors/aboutme.mpl?userid=edjones><B>edjones(8007)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=edjones><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=edjones><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=202120\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let s=hrs sammy takes and m=hrs martin takes<BR>\n" );
document.write( "s=m+5<BR>\n" );
document.write( "in 1 hr martin gets 1/m of the job done and sammy gets 1/(m+5) done.<BR>\n" );
document.write( "1/m + 1/(m+5) = 1/6<BR>\n" );
document.write( "6(m+5)+6m=m(m+5)<BR>\n" );
document.write( "6m+30+6m=m^2+5m<BR>\n" );
document.write( "m^2-7m-30=0<BR>\n" );
document.write( "(m-10)(m+3)=0<BR>\n" );
document.write( "m=10 hrs<BR>\n" );
document.write( "s=15 hrs<BR>\n" );
document.write( ".<BR>\n" );
document.write( "Ed </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );