document.write( "Question 277164: I want to find the value of a, b, and c so that i can decompose it into partial functions\r
\n" ); document.write( "\n" ); document.write( "(8x-3)/(2x^2-x)\r
\n" ); document.write( "\n" ); document.write( "thanks!!!
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Algebra.Com's Answer #202117 by ankor@dixie-net.com(22740)\"\" \"About 
You can put this solution on YOUR website!
\"%288x-3%29%2F%282x%5E2-x%29\" = \"%288x-3%29%2Fx%282x-1%29\"
\n" ); document.write( "Write the given expression as a sum using A & B
\n" ); document.write( "\"%288x-3%29%2Fx%282x-1%29\" = \"A%2Fx\" + \"B%2F%282x-1%29\"
\n" ); document.write( ":
\n" ); document.write( "Simplify by multipling each side by the LCD, x(2x-1)
\n" ); document.write( "x(2x-1)*\"%288x-3%29%2Fx%282x-1%29\" = x(2x-1)*\"A%2Fx\" + x(2x-1)*(\"B%2F%282x-1%29\"
\n" ); document.write( "Results
\n" ); document.write( "8x - 3 = A(2x-1) + Bx
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\n" ); document.write( "8x - 3 = A2x - A + Bx
\n" ); document.write( ":
\n" ); document.write( "8x - 3 = x(2A + B) - A
\n" ); document.write( "The coefficient on one side = the coefficient on the other side
\n" ); document.write( "2A + B = 8
\n" ); document.write( "the constant on one side = the constant on the other side
\n" ); document.write( "-A = -3
\n" ); document.write( "A = 3
\n" ); document.write( "Substitute 3 for A and find B
\n" ); document.write( "2(3) + B = 8
\n" ); document.write( "B = 8 - 6
\n" ); document.write( "B = 2
\n" ); document.write( "So we have
\n" ); document.write( "\"%288x-3%29%2Fx%282x-1%29\" = \"3%2Fx\" + \"2%2F%282x-1%29\"
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