document.write( "Question 277644: One number is 3 more than 2 times the other, and their sum is 27. Find the numbers.\r
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document.write( "The sum of 2 consecutive odd integers is 92. Find the numbers.\r
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document.write( "One number is 800 less than 3 times the other, and their sum is 1,200. Find the numbers.\r
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document.write( "The length of a rectangle is 3 times the width, and the perimeter is 22. Find the dimensions of the rectangle. Width is___, Lenght is___ \n" );
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Algebra.Com's Answer #202096 by mananth(16946)![]() ![]() You can put this solution on YOUR website! Let one number be x\r \n" ); document.write( "\n" ); document.write( "The other number is 3 more than 2x = 2x+3\r \n" ); document.write( "\n" ); document.write( "x+2x+3=27\r \n" ); document.write( "\n" ); document.write( "3x=27-3\r \n" ); document.write( "\n" ); document.write( "3x=24\r \n" ); document.write( "\n" ); document.write( "x=24/3 \n" ); document.write( "=8\r \n" ); document.write( "\n" ); document.write( "The other number is 19\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Let the width be x\r \n" ); document.write( "\n" ); document.write( "the length = 3times the width = 3x\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "perimeter = 2x+2*3x\r \n" ); document.write( "\n" ); document.write( "2x+6x=22\r \n" ); document.write( "\n" ); document.write( "8x=22 \n" ); document.write( "x=22/8 \n" ); document.write( "x=2.75\r \n" ); document.write( "\n" ); document.write( "Length = 3*2.75 =8.25\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Let the odd number be x\r \n" ); document.write( "\n" ); document.write( "The next odd number will be x+2\r \n" ); document.write( "\n" ); document.write( "Their sum =92\r \n" ); document.write( "\n" ); document.write( "x+x+2=92\r \n" ); document.write( "\n" ); document.write( "2x+2-92\r \n" ); document.write( "\n" ); document.write( "2x=92-2 \n" ); document.write( "2x=90\r \n" ); document.write( "\n" ); document.write( "x=90/2 \n" ); document.write( "=45\r \n" ); document.write( "\n" ); document.write( "the other number will be 47\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Let the number be x\r \n" ); document.write( "\n" ); document.write( "The other number is 800 less than 3times x\r \n" ); document.write( "\n" ); document.write( "3x-800\r \n" ); document.write( "\n" ); document.write( "x+3x-800=1200\r \n" ); document.write( "\n" ); document.write( "4x-800 =1200\r \n" ); document.write( "\n" ); document.write( "4x=1200+800\r \n" ); document.write( "\n" ); document.write( "4x=2000/4\r \n" ); document.write( "\n" ); document.write( "x=500\r \n" ); document.write( "\n" ); document.write( "The other number 1200-500 = 700\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |