document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=277623>Question 277623</A>: <I><SPAN STYLE=\"word-break: break-all;\"> It says the outside dimensions of a picture frame are 4 feet by 29 inches.If its inside dimensions are 1 3/4 feet by 21 inches what is the area of the frame?\r<BR>\n" );
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document.write( "I dont understand where to start HELP?!?! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #202095 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=202095\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> It says the outside dimensions of a picture frame are 4 feet by 29 inches.If its inside dimensions are 1 3/4 feet by 21 inches what is the area of the frame?\r<BR>\n" );
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document.write( "I dont understand where to start HELP?!?!\r<BR>\n" );
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document.write( "4feet = 48 inches <BR>\n" );
document.write( "Outside area = 48*29= 1392 square inches\r<BR>\n" );
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document.write( "1 3/4 feet = 21 inches\r<BR>\n" );
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document.write( "Indise area = 21 *21 =441 sq. inches\r<BR>\n" );
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document.write( "Difference between the outer area and the inner area will give the area of the frame\r<BR>\n" );
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document.write( "1392-441=951 square inches  </SPAN>\n" );
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