document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=33814>Question 33814</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The sum of the measures of the angles in any triangle is 180 degrees. In triangle ABC, angle A is five more than twice the measure of angle B. Angle C is five less than three times the measure of angle B. \r<BR>\n" );
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document.write( "I tried: 2b+5=A 3B{c-5} \r<BR>\n" );
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document.write( "No luck </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #20206 by </B><A HREF=/tutors/aboutme.mpl?userid=venugopalramana><B>venugopalramana(3286)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=venugopalramana><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.geocities.com/venugopalramana/FREE_MATHS_ASSISTANCE.html valign=middle><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=20206\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The sum of the measures of the angles in any triangle is 180 degrees. In triangle ABC, angle A is five more than twice the measure of angle B. Angle C is five less than three times the measure of angle B.<BR>\n" );
document.write( "I tried: 2b+5=A 3B{c-5} <BR>\n" );
document.write( "GO STEP BY STEP AND GO SYSTEMATICALLY.<BR>\n" );
document.write( "SINCE B HAS COMMON RELATION WITH BOTH A AND C..START WITH THAT<BR>\n" );
document.write( "LET ANGLE B =B<BR>\n" );
document.write( "LET US FIND A..<BR>\n" );
document.write( "TWICE THIS =2B<BR>\n" );
document.write( "5 MORE THAN THIS =2B+5=A\r<BR>\n" );
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document.write( "LET US FIND C...<BR>\n" );
document.write( "THREE TIMES B..=3B<BR>\n" );
document.write( "5 LESS THAN THIS ...<BR>\n" );
document.write( "3B-5=C\r<BR>\n" );
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document.write( "SO NOW SUM UP THE 3 ANGLES...<BR>\n" );
document.write( "A+B+C=2B+5+B+3B-5=180<BR>\n" );
document.write( "6B=180<BR>\n" );
document.write( "B=30<BR>\n" );
document.write( "SO A=2B+5=2*30+5=65<BR>\n" );
document.write( "C=3B-5=3*30-5=85 </SPAN>\n" );
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