document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=277507>Question 277507</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The diameter of the base of a cone is 18 feet. The hight of the cone is 12 feet. What is the volume of the cone? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #202023 by </B><A HREF=/tutors/aboutme.mpl?userid=dabanfield><B>dabanfield(803)</B></A><img src=\"/images/stars/stars-11.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=dabanfield><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=202023\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The formula for the volume of a cone is:\r<BR>\n" );
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document.write( "1/3*area of the base*height\r<BR>\n" );
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document.write( "The base is a circle with diameter 18 so the area of the base is pi*r^2 = pi*9^2 = 81*pi.\r<BR>\n" );
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document.write( "The area volume of the cone then is:\r<BR>\n" );
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document.write( "(1/3)*(81*pi)*12 =<BR>\n" );
document.write( "324*pi </SPAN>\n" );
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