document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=277440>Question 277440</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The sum of three numbers is 138. The second is 5 more than the smallest and the third is 10 more than the smallest. Find the numbers. Thank you </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #201982 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=201982\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The sum of three numbers is 138. The second is 5 more than the smallest and the third is 10 more than the smallest. Find the numbers. Thank you\r<BR>\n" );
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document.write( "Let the smallest number be x\r<BR>\n" );
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document.write( "second will be x+5\r<BR>\n" );
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document.write( "third will be x+10\r<BR>\n" );
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document.write( "x+x+5+x+10=138\r<BR>\n" );
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document.write( "3x+15=138\r<BR>\n" );
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document.write( "3x=138-15<BR>\n" );
document.write( "3x=123<BR>\n" );
document.write( "x=123/3<BR>\n" );
document.write( "=41\r<BR>\n" );
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document.write( "the numbers are 41, 46 and 51 </SPAN>\n" );
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