document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=277442>Question 277442</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How many pounds of a certain alloy containing 35% silver must be melted with another alloy containing 65% silver to obtain 50 pounds of an alloy containing 50% silver? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #201981 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=201981\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> How many pounds of a certain alloy containing 35% silver must be melted with another alloy containing 65% silver to obtain 50 pounds of an alloy containing 50% silver?\r<BR>\n" );
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document.write( "let us mix x pounds of 35% alloy\r<BR>\n" );
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document.write( "So the 65% alloy mixed will be 50-x pounds\r<BR>\n" );
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document.write( "when added the mix is 50 pound and 50% \r<BR>\n" );
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document.write( "0.35x+0.65(50-x)=0.5*50\r<BR>\n" );
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document.write( "0.35x+32.5 - 0.65x = 25\r<BR>\n" );
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document.write( "-0.3x=-32.5+25\r<BR>\n" );
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document.write( "-0.3x= -7.5\r<BR>\n" );
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document.write( "x=7.5/0.3   = 25  pounds of 35% silver alloy\r<BR>\n" );
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