document.write( "Question 33803: One conveyor belt can move 1000 boxes in 12 minutes. Another can move 1000 boxes in 9 minutes. If another conveyor is added and all three are used, the boxes are moved in 3 minutes. How long would it take the third conveyor belt alone to do the same job? \n" ); document.write( "
Algebra.Com's Answer #20198 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! 1st belt Data: \n" ); document.write( " time=12 min ; rate = 1/12 job/min \n" ); document.write( "2nd belt Data: \n" ); document.write( " time=9 min ; rate = 1/9 job/min \n" ); document.write( "3rd belt Data: \n" ); document.write( " time= x min ; rate = 1/x job/min \n" ); document.write( "Together Data: \n" ); document.write( " time= 3 min ; rate = 1/3 job/min \n" ); document.write( "EQUATION: \n" ); document.write( "rate + rate + rate= 1/3 \n" ); document.write( "1/12 + 1/9 + 1/x = 1/3 \n" ); document.write( "Multiply thru by 36x to get: \n" ); document.write( "3x + 4x + 36 = 12x \n" ); document.write( "5x=36 \n" ); document.write( " x=7.2 minutes (time for the 3rd belt working alone) \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " |