document.write( "Question 33804: Please help me with this question: Name the x-intercepts and the vertex of the graph of y=(x+3)(x-1). Then sketch the graph of the function. \n" ); document.write( "
Algebra.Com's Answer #20197 by stanbon(75887)\"\" \"About 
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To find the x-intercepts, let y=0 and solve for \"x\", as follows:
\n" ); document.write( "0=(x+3)(x-1)
\n" ); document.write( "Since the product is zero one of the factors is zero.
\n" ); document.write( "If x+3=0 then x=-3
\n" ); document.write( "If x-1=0 then x=1
\n" ); document.write( "x-intercepts are (-3,0) and (1,0)
\n" ); document.write( "VERTEX:
\n" ); document.write( "Rewrite the equation as follows:
\n" ); document.write( "y=x^2+2x-3
\n" ); document.write( "Complete the square, as follows:
\n" ); document.write( "y+3=x^2+2x
\n" ); document.write( "y+3+1=x^2+2x+1
\n" ); document.write( "y+4=(x+1)^2
\n" ); document.write( "Vertex is at x=-1, y=-4
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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