document.write( "Question 277282: how do i do a problem like this -16x+2y=-6 through point (16,8) \n" ); document.write( "
Algebra.Com's Answer #201962 by oberobic(2304)\"\" \"About 
You can put this solution on YOUR website!
First, get the equation into slope-intercept form: y = mx+b
\n" ); document.write( "-16x + 2y = -6
\n" ); document.write( "2y = 16x - 6
\n" ); document.write( "y = 8x - 3
\n" ); document.write( ".
\n" ); document.write( "But this line does NOT go through the point (16,8), as we can see on a graph.
\n" ); document.write( "\"graph%28500%2C500%2C-20%2C20%2C-20%2C20%2C8%2Ax-3%29\"
\n" ); document.write( "In fact, y = 125 when x=16.
\n" ); document.write( ".
\n" ); document.write( "However, the general equation y = mx+b can be shifted with any constant 'b'.
\n" ); document.write( "8 = 8(16) + b
\n" ); document.write( "8 = 128 + b
\n" ); document.write( "b = -120
\n" ); document.write( "We can graph this as follows.
\n" ); document.write( "\"graph%28500%2C500%2C-5%2C20%2C-5%2C20%2C8%2Ax-120%29\"
\n" ); document.write( "So the equation y = 8x - 120 will have slope = 8 and it will go through the point (16,8).
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\n" ); document.write( "We can check this answer by remembering the slope = rise / run = change in y / change in x.
\n" ); document.write( "The slope m = 8.
\n" ); document.write( "So if we move one point on the x-axis, there will be a change of 8 on the y-axis.
\n" ); document.write( "Given (16,8), we can predict that (15,0) will be on the line. (-1 on the x-axis leads to -8 on the y-axis)
\n" ); document.write( "And we can predict (17,16) will be on the line. (+1 on the x-axis leads to +8 on the y-axis)
\n" ); document.write( "Looking back at the second graph, we see that is the case.
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