document.write( "Question 277315: one acetic acid solution is 70% water and another is 30% water. how many liters of each solution should be mixed to produce 20 liters of a solution that is 40% water? \n" ); document.write( "
Algebra.Com's Answer #201960 by oberobic(2304)\"\" \"About 
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With 'solution' problems, you have to keep track of how much pure stuff you need.
\n" ); document.write( "This question is tricky because the question presents the complementary percentages.
\n" ); document.write( "Solution 1 is 70% water, so it is 30% pure acetic acid. We normally call that a 30% solution.
\n" ); document.write( "Solution 2 is 30% water, so it is 70% pure acetic acid. We normally call that a 70% solution.
\n" ); document.write( "The goal is 20 liters of a 60% acetic acid solution.
\n" ); document.write( ".
\n" ); document.write( "x = volume of 30% solution
\n" ); document.write( "20 - x = volume of 70% solution
\n" ); document.write( ".
\n" ); document.write( ".3x = amount of pure acetic acid
\n" ); document.write( ".7(20-x) = the other amount of pure acetic acid.
\n" ); document.write( ".
\n" ); document.write( "20 liters of 60% acetic acid will have .6*20 = 12 liters of pure acetic acid.
\n" ); document.write( ".
\n" ); document.write( ".3x + .7(20-x) = 12
\n" ); document.write( ".
\n" ); document.write( ".3x + 14 - .7x = 12
\n" ); document.write( "-.4x = -2
\n" ); document.write( "x = -2/-.4 = 5 liters of 30% solution
\n" ); document.write( "which means there is
\n" ); document.write( "15 liters of 70% solution.
\n" ); document.write( ".
\n" ); document.write( "checking to see if we have 12 L of pure acetic acid
\n" ); document.write( ".
\n" ); document.write( ".3*5 + .7*15 = 1.5 + 10.5 = 12
\n" ); document.write( ".
\n" ); document.write( "So, 5 liters of 30% acetic acid + 15 liters of 70% acetic acid results in 20 liters of 60% acetic acid solution.
\n" ); document.write( ".
\n" ); document.write( "Reviewing the question, we need to give the complementary answer in terms of percentage of water.
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\n" ); document.write( "Answer:
\n" ); document.write( "5 liters of 70% water + 15 liters of 30% water = 20 liters of 40% water
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