document.write( "Question 277304: What is the smallest positive value for s where y=sin2x reaches its maximum?\r
\n" ); document.write( "\n" ); document.write( "a. pie over 4
\n" ); document.write( "b. pie
\n" ); document.write( "c. 3pie over 2
\n" ); document.write( "d. 2pie
\n" ); document.write( "e. 5pie over 2
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Algebra.Com's Answer #201957 by Alan3354(69443)\"\" \"About 
You can put this solution on YOUR website!
What is the smallest positive value for s where y=sin2x reaches its maximum?
\n" ); document.write( "a. pie over 4
\n" ); document.write( "b. pie
\n" ); document.write( "c. 3pie over 2
\n" ); document.write( "d. 2pie
\n" ); document.write( "e. 5pie over 2
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\n" ); document.write( "The sine is a max at pi/2 (pi, the Greek letter, not pie, the dessert).
\n" ); document.write( "If 2x = pi/2, then x = pi/4 ( = 45º)
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\n" ); document.write( "I think you meant to say x, not s.
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