document.write( "Question 277305: I need help with this problem. The inner rectangle whose length is 7 inches and width is 13 inches is surrounded by a rectanglar frame whose uniform thickness is 2.5 inches. Find the area. \n" ); document.write( "

Algebra.Com's Answer #201936 by mananth(16949) $\"\"$ $\"About$

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I need help with this problem. The inner rectangle whose length is 7 inches and width is 13 inches is surrounded by a rectanglar frame whose uniform thickness is 2.5 inches. Find the area.\r
\n" ); document.write( "\n" ); document.write( "length = 7 inches \r
\n" ); document.write( "\n" ); document.write( "width = 13 inches\r
\n" ); document.write( "\n" ); document.write( "rectangular frame width = 2.5 inches. This width is on both sides of the length and width\r
\n" ); document.write( "\n" ); document.write( "Add 5 to width and length\r
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\n" ); document.write( "\n" ); document.write( "The length then becomes 7+5 = 12 inches
\n" ); document.write( "width becomes 13+5 = 18 inche.\r
\n" ); document.write( "\n" ); document.write( "The area including frame = 12 * 18 =216 sq. inches\r
\n" ); document.write( "\n" ); document.write( "Original area = 7*13= 91 square inches\r
\n" ); document.write( "\n" ); document.write( "the difference will give area of the frame \n" ); document.write( "

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