document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=277300>Question 277300</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If a central angle of measure 30degrees is subtended by a circular arc of length 6 meters, how many meters in length is the radius of the circle? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #201933 by </B><A HREF=/tutors/aboutme.mpl?userid=dabanfield><B>dabanfield(803)</B></A><img src=\"/images/stars/stars-11.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=dabanfield><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=201933\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> If a central angle of measure 30degrees is subtended by a circular arc of length 6 meters, how many meters in length is the radius of the circle?\r<BR>\n" );
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document.write( "If the radius of the circle is R then the circumference is pi*2*R so we have:\r<BR>\n" );
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document.write( "30/360 = 6/(2*R*pi)\r<BR>\n" );
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document.write( "30 = (6*360)/2*R+pi)<BR>\n" );
document.write( "30*(2*R*pi) = 6*360<BR>\n" );
document.write( "2*R*pi = 72<BR>\n" );
document.write( "R = 72/(2*pi)<BR>\n" );
document.write( "R = 36/pi </SPAN>\n" );
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