document.write( "Question 276924: Karin biked at 13 mph for a time but got a flat tire. She then walked at 5 mph. She traveled a total of 93 miles. Had she biked the whole time, she would have gone 117 miles. How many hours did she walk?
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Algebra.Com's Answer #201904 by ankor@dixie-net.com(22740)\"\" \"About 
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Karin biked at 13 mph for a time but got a flat tire.
\n" ); document.write( " She then walked at 5 mph. She traveled a total of 93 miles.
\n" ); document.write( " Had she biked the whole time, she would have gone 117 miles.
\n" ); document.write( " How many hours did she walk?
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\n" ); document.write( "Let b = biking time
\n" ); document.write( "Let w = walking time
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\n" ); document.write( "Write a distance equation for each scenario
\n" ); document.write( "13b + 5w = 93
\n" ); document.write( "13(b+w) = 117
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\n" ); document.write( "13b + 13w = 117
\n" ); document.write( "13b = 5w = 93
\n" ); document.write( "--------------------subtraction eliminates b, find w
\n" ); document.write( "0b + 8w = 24
\n" ); document.write( "w = \"24%2F8\"
\n" ); document.write( "w = 3 hrs walking time
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\n" ); document.write( "To check solution find biking time
\n" ); document.write( "13b + 5(3) = 93
\n" ); document.write( "13b + 15 = 93
\n" ); document.write( "13b = 93 - 15
\n" ); document.write( "13b = 78
\n" ); document.write( "b = \"78%2F15\"
\n" ); document.write( "b = 6 hrs on the bike
\n" ); document.write( ":
\n" ); document.write( "using the all bike equation
\n" ); document.write( "13(6 + 3) = 117
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