document.write( "Question 4435: if f(x-2)= x+3/x-4 then f(5)= \n" ); document.write( "
Algebra.Com's Answer #2019 by rapaljer(4671)\"\" \"About 
You can put this solution on YOUR website!
In this formula, \"f%28x-2%29+=+%28x%2B3%29%3F%28x-4%29\", in order to get f(5), you will have to let x= 7. Then when you let x=7, you'll have \r
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\n" ); document.write( "\n" ); document.write( "\"f%287-2%29+=+f%285%29+=+%287%2B3%29%2F%287-4%29\" so \"f%285%29+=+10%2F3\"\r
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\n" ); document.write( "\n" ); document.write( "Please accept my apologies to the student who wrote Question # 4436. In my attempt to answer the question, I accidentally deleted the question, and I can't get it back. However, here is the question:\r
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\n" ); document.write( "\n" ); document.write( "logarithm/4436: some of the values of the functions F an G are in the table. the value of G(f(3)) is Values
\n" ); document.write( "x 1,2,3,4
\n" ); document.write( "f(x) 3,1,4,2
\n" ); document.write( "G(X)3,4,2,1\r
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\n" ); document.write( "\n" ); document.write( "And this is the solution to that question:\r
\n" ); document.write( "\n" ); document.write( "It might help to write this in the following way, so corresponding values line up better:\r
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\n" ); document.write( "\n" ); document.write( "x = 1, 2, 3, 4
\n" ); document.write( "f = 3, 1, 4, 2
\n" ); document.write( "G = 3, 4, 2, 1\r
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\n" ); document.write( "\n" ); document.write( "First, in order to find G(f(3)}, you need to start by finding f(3). This notation means that x=3, so look for the f value that corresponds to x=3. At x=3, right below that you will find that f(3)=4.\r
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\n" ); document.write( "\n" ); document.write( "So, G(f(3)) = G(4), which means to look in the G row, across to where x=4. If x=4, the G(4) = 1, so the final answer is 1. \r
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\n" ); document.write( "\n" ); document.write( "Sorry about the deletion. However, what you got is TWO for the price of ONE. \r
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\n" ); document.write( "\n" ); document.write( "R^2 from SCC
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