document.write( "Question 277136: I have a triangle PQR. Point G is located between P&Q and point J is located between P&R. Given the information below I need to find the values of x and y so that JG is parallel to RQ.\r
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document.write( "RQ=10
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document.write( "JG=8
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document.write( "PJ=8x-5
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document.write( "JR=x
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document.write( "PG=3y+2
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document.write( "QG=y\r
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document.write( "(I know that the answer's are 5/4 and 2 but I am not sure how??????)
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document.write( "Thanks for your help.\r
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Algebra.Com's Answer #201855 by scott8148(6628)![]() ![]() You can put this solution on YOUR website! for JG to be parallel to RQ, the two sides (PQ and PR) must be divided in equal ratios by JG \n" ); document.write( "___ this is the same ratio as JG/RQ\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "PJ / (PJ + JR) = JG / RQ\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "(8x - 5) / (8X - 5 + x) = 8 / 10 ___ 80x - 50 = 72x - 40 ___ 8x = 10 ___ x = 5/4\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "PG / (PG + QG) = JG / RQ\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "(3y + 2) / (3y + 2 + y) = 8 / 10 ___ 30y + 20 = 32y + 16 ___ 4 = 2y ___ 2 = y \n" ); document.write( " |