document.write( "Question 276413: 32x^6y^9/z^8\r
\n" ); document.write( "\n" ); document.write( "all under a third root sign
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Algebra.Com's Answer #201840 by jsmallt9(3758)\"\" \"About 
You can put this solution on YOUR website!
\"root%283%2C+32x%5E6y%5E9%2Fz%5E8%29\"
\n" ); document.write( "Simplifying a cube root involves finding perfect cubes. Since there is a denominator we will also want to rationalize the denominator. I'm going to make the denominator a perfect cube at the start. This will take care of the rationalizing denomiinator before we start. Since any exponent that is divisible by 3 is a perfect cube, all I need to do is change \"z%5E8\" to \"z%5E9\":
\n" ); document.write( "\"root%283%2C+%2832x%5E6y%5E9%2Fz%5E8%29%28z%2Fz%29%29\"
\n" ); document.write( "which simplifies to:
\n" ); document.write( "\"root%283%2C+32x%5E6y%5E9z%2Fz%5E9%29\"
\n" ); document.write( "Now we can start finding perfect cubes:
\n" ); document.write( "\"root%283%2C+2%5E3%2A4%28x%5E2%29%5E3%28y%5E3%29%5E3z%2F%28z%5E3%29%5E3%29\"
\n" ); document.write( "Using the properties of radicals we can separate out all the perfect cubes:
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\n" ); document.write( "Replacing the cube roots of the perfect cubes we get:
\n" ); document.write( "\"%282%2Aroot%283%2C+4%29%2Ax%5E2%2Ay%5E3%2Aroot%283%2C+z%29%29%2Fz%5E3\"
\n" ); document.write( "Rearranging the factors in the numerator and combining the remaining radicals we get:
\n" ); document.write( "\"%282x%5E2y%5E3%2Aroot%283%2C+4z%29%29%2Fz%5E3\"
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