document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=277161>Question 277161</A>: <I><SPAN STYLE=\"word-break: break-all;\"> find a number whose half exceeds its third by the sum of its digits. give the formula. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #201834 by </B><A HREF=/tutors/aboutme.mpl?userid=CharlesG2><B>CharlesG2(834)</B></A><img src=\"/images/stars/stars-11.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=CharlesG2><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=201834\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> find a number whose half exceeds its third by the sum of its digits. give the formula.\r<BR>\n" );
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document.write( "x = a number<BR>\n" );
document.write( "y = sum of x's digits\r<BR>\n" );
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document.write( "half exceeds its third by an amount (in this case the amount is the sum of the digits of the number) means that the half equals the third plus the amount\r<BR>\n" );
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document.write( "1/2 * x = 1/3 * x + y (convert to 6ths)<BR>\n" );
document.write( "3/6 * x = 2/6 * x + y<BR>\n" );
document.write( "1/6 * x = y (multiply both sides by 6)<BR>\n" );
document.write( "x = 6y<BR>\n" );
document.write( "so that means the number will be 6 times the sum of its digits\r<BR>\n" );
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document.write( "example answer would be 54, 6 * (5 + 4) = 6 * 9 = 54<BR>\n" );
document.write( "                       27 = 18 + 9 = 27<BR>\n" );
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