document.write( "Question 277151: how do u solve this equation? \"3x%5E2%2B5x-2=0\" \n" ); document.write( "
Algebra.Com's Answer #201828 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
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Solved by pluggable solver: Quadratic Formula
Let's use the quadratic formula to solve for x:

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\n" ); document.write( " Starting with the general quadratic
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\n" ); document.write( " \"ax%5E2%2Bbx%2Bc=0\"
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\n" ); document.write( " the general solution using the quadratic equation is:
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\n" ); document.write( " \"x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29\"
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\n" ); document.write( " So lets solve \"3%2Ax%5E2%2B5%2Ax-2=0\" ( notice \"a=3\", \"b=5\", and \"c=-2\")
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\n" ); document.write( " \"x+=+%28-5+%2B-+sqrt%28+%285%29%5E2-4%2A3%2A-2+%29%29%2F%282%2A3%29\" Plug in a=3, b=5, and c=-2
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\n" ); document.write( " \"x+=+%28-5+%2B-+sqrt%28+25-4%2A3%2A-2+%29%29%2F%282%2A3%29\" Square 5 to get 25
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\n" ); document.write( " \"x+=+%28-5+%2B-+sqrt%28+25%2B24+%29%29%2F%282%2A3%29\" Multiply \"-4%2A-2%2A3\" to get \"24\"
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\n" ); document.write( " \"x+=+%28-5+%2B-+sqrt%28+49+%29%29%2F%282%2A3%29\" Combine like terms in the radicand (everything under the square root)
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\n" ); document.write( " \"x+=+%28-5+%2B-+7%29%2F%282%2A3%29\" Simplify the square root (note: If you need help with simplifying the square root, check out this solver)
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\n" ); document.write( " \"x+=+%28-5+%2B-+7%29%2F6\" Multiply 2 and 3 to get 6
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\n" ); document.write( " So now the expression breaks down into two parts
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\n" ); document.write( " \"x+=+%28-5+%2B+7%29%2F6\" or \"x+=+%28-5+-+7%29%2F6\"
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\n" ); document.write( " Lets look at the first part:
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\n" ); document.write( " \"x=%28-5+%2B+7%29%2F6\"
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\n" ); document.write( " \"x=2%2F6\" Add the terms in the numerator
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\n" ); document.write( " \"x=1%2F3\" Divide
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\n" ); document.write( " So one answer is
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\n" ); document.write( " \"x=1%2F3\"
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\n" ); document.write( " Now lets look at the second part:
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\n" ); document.write( " \"x=%28-5+-+7%29%2F6\"
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\n" ); document.write( " \"x=-12%2F6\" Subtract the terms in the numerator
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\n" ); document.write( " \"x=-2\" Divide
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\n" ); document.write( " So another answer is
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\n" ); document.write( " \"x=-2\"
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\n" ); document.write( " So our solutions are:
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\n" ); document.write( " \"x=1%2F3\" or \"x=-2\"
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