document.write( "Question 4396: I need Help understanding how to do these:\r
\n" ); document.write( "\n" ); document.write( "\"log%28+4%2C+%28x-2%29+%29%2Blog%284%2C+%28x-8%29+%29=+2\"
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Algebra.Com's Answer #2018 by ichudov(507)\"\" \"About 
You can put this solution on YOUR website!
My obligatory cartoon: \r
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\n" ); document.write( "\n" ); document.write( "Exponentiate both sides, that is, take 4 to the power of both sides:\r
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\n" ); document.write( "\n" ); document.write( "\"4%5E%28log%28+4%2C+%28x-2%29+%29%2Blog%284%2C+%28x-8%29+%29%29=+4%5E2\"\r
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\n" ); document.write( "\n" ); document.write( "\"%284%5Elog%28+4%2C+%28x-2%29+%29%29+%2A+%284%5Elog%284%2C+%28x-8%29+%29%29=+4%5E2\"\r
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\n" ); document.write( "\n" ); document.write( "Note that \"a%5Elog%28a%2C+b%29+=+b\", so \"4%5Elog%28+4%2C+%28x-2%29+%29+=+x-2\".\r
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\n" ); document.write( "\n" ); document.write( "\"%28x-2%29%2A%28x-8%29+=+4%5E2+=+16\"\r
\n" ); document.write( "\n" ); document.write( "\"%28x-2%29%2A%28x-8%29+=+16\"\r
\n" ); document.write( "\n" ); document.write( "that simplifies to a simple quadratic equation, solve it. x=10 is one obvious answer, there could be another.
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