document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=277073>Question 277073</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Six consecutive integers are given. The sum of the second, fourth and fifth is 41. The sum of the third and sixth is:\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #201796 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley77><B>checkley77(12844)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley77><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=201796\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let x,x+1,x+2,x+3,x+4,x+5 be the 6 integers.<BR>\n" );
document.write( "x+1+x+3+x+4=41<BR>\n" );
document.write( "3x+8=41<BR>\n" );
document.write( "3x=41-8<BR>\n" );
document.write( "3x=33<BR>\n" );
document.write( "x=11 ans.<BR>\n" );
document.write( "11+2+11+5<BR>\n" );
document.write( "13+16=29 ans. </SPAN>\n" );
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