document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=33781>Question 33781</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I THINK I MIISED TYPED THE QUESTION BEFORE\r<BR>\n" );
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document.write( "1.JANE PICKED A NUMBER ADDED 3 TO IT MULTIPLIED THE SUM BY 5 THEN SUBTRACTED 8 AND DOUBLED THE RESULT. IF THE ANSWER WAS 44 WHAT NUMBER DID SHE START WITH\r<BR>\n" );
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document.write( "2.JUDY RODE HER BIKE 4 BLOCKS EAST 8 BLOCKS SOUTH 9 BLOCKS WESR AND 4 BLOCKS NORTH HOW MANY BLOCKS WEST AND SOUTH OF HER STARTING POINT WAS SHE? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #20178 by </B><A HREF=/tutors/aboutme.mpl?userid=Nate><B>Nate(3500)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Nate><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=20178\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 1.JANE PICKED A NUMBER ADDED 3 TO IT MULTIPLIED THE SUM BY 5 THEN SUBTRACTED 8 AND DOUBLED THE RESULT. IF THE ANSWER WAS 44 WHAT NUMBER DID SHE START WITH<BR>\n" );
document.write( "2(5(x+3)-8)=44<BR>\n" );
document.write( "2(5x+15-8)=44<BR>\n" );
document.write( "2(5x+7)=44<BR>\n" );
document.write( "10x+14=44<BR>\n" );
document.write( "10x=30<BR>\n" );
document.write( "x=3 the number is three<BR>\n" );
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document.write( "2.JUDY RODE HER BIKE 4 BLOCKS EAST 8 BLOCKS SOUTH 9 BLOCKS WESR AND 4 BLOCKS NORTH HOW MANY BLOCKS WEST AND SOUTH OF HER STARTING POINT WAS SHE?<BR>\n" );
document.write( "If you draw the route on a cordinate plane and start the bicycle at the origin, you get the starting point (0,0) and the end point (-5,-4)<BR>\n" );
document.write( "distance formula: d = ((y(sub 2)-y(sub 1))+(x(sub 2)-x(sub 1)))^(1/2)<BR>\n" );
document.write( "d = ((y(sub 2)-y(sub 1))^2+(x(sub 2)-x(sub 1))^2)^(1/2) use (0,0) and (-5,-4)<BR>\n" );
document.write( "d = ((-4-0)^2 + (-5-0)^2)^(1/2)<BR>\n" );
document.write( "d = ((-4)^2 + (-5)^2)^(1/2)<BR>\n" );
document.write( "d = (16 + 25)^(1/2)<BR>\n" );
document.write( "d = (41)^(1/2) is your distance (also named as the square root of 41) </SPAN>\n" );
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