document.write( "Question 276733: when the digits of a two-digit number are reversed, the new number is 9 more than the original number, and the sum of the digits of the original number is 13. What is the original number?
\n" ); document.write( "Can you solve using the 5-step method.
\n" ); document.write( "Please and thank you! \n" ); document.write( "
Algebra.Com's Answer #201737 by ankor@dixie-net.com(22740)\"\" \"About 
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when the digits of a two-digit number are reversed, the new number is 9 more than the original number,
\n" ); document.write( "and the sum of the digits of the original number is 13.
\n" ); document.write( "What is the original number?
\n" ); document.write( ":
\n" ); document.write( "Let x = the 10's digit
\n" ); document.write( "Let y = the units
\n" ); document.write( "then
\n" ); document.write( "10x + y = \"the number\"
\n" ); document.write( ":
\n" ); document.write( "Write an equation for each statement:
\n" ); document.write( "\"the digits of a two-digit number are reversed, the new number is 9 more than the original number,\"
\n" ); document.write( "10y + x = 10x + y + 9
\n" ); document.write( "Combine like terms
\n" ); document.write( "10y - y = 10x - x + 9
\n" ); document.write( "9y = 9x + 9
\n" ); document.write( "Simplify, divide by 9
\n" ); document.write( "y = (x + 1)
\n" ); document.write( ":
\n" ); document.write( "\"the sum of the digits of the original number is 13.\"
\n" ); document.write( "x + y = 13
\n" ); document.write( "Substitute (x+1) for y
\n" ); document.write( "x + (x+1) = 13
\n" ); document.write( "2x = 13 - 1
\n" ); document.write( "2x = 12
\n" ); document.write( "x = 6 is the 10's digit
\n" ); document.write( "then since the sum is 13, obviously
\n" ); document.write( "y = 7 is the units
\n" ); document.write( "and
\n" ); document.write( "67 is the original two digit number
\n" ); document.write( ":
\n" ); document.write( "Check this in the statement:
\n" ); document.write( "\"when the digits of a two-digit number are reversed, the new number is 9 more than the original number,
\n" ); document.write( "76 = 67 + 9
\n" ); document.write( ":
\n" ); document.write( "When the number 67 if reversed it is 9 more than the original \n" ); document.write( "
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