document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=276847>Question 276847</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the sum of the ages of three children is 32 the age of the oldest is twice the age of the youngest the ages of the two oldest differ between 3 years what are the ages of the three children? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #201706 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=201706\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> the sum of the ages of three children is 32 the age of the oldest is twice the age of the youngest the ages of the two oldest differ between 3 years what are the ages of the three children?\r<BR>\n" );
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document.write( "let the youngest be x\r<BR>\n" );
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document.write( "The oldest will be 2x\r<BR>\n" );
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document.write( "The other child's age will be 32- (2x+x)\r<BR>\n" );
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document.write( "2x - (32-3x)=3\r<BR>\n" );
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document.write( "2x-32 +3x=3\r<BR>\n" );
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document.write( "5x=35\r<BR>\n" );
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document.write( "x= 7  the youngest\r<BR>\n" );
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document.write( "the oldest will be 14  years\r<BR>\n" );
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document.write( "The third child will be 11 years\r<BR>\n" );
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document.write( " </SPAN>\n" );
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