document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=276700>Question 276700</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The sum of three numbers is 94. The first number is 6 less than the second . The third number is 3 times the second. What are the numbers? <BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #201663 by </B><A HREF=/tutors/aboutme.mpl?userid=nyc_function><B>nyc_function(2741)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=nyc_function><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=nyc_function><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=201663\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let (x - 6) = first number\r<BR>\n" );
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document.write( "Let x = the second number\r<BR>\n" );
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document.write( "Let 3x = the third number\r<BR>\n" );
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document.write( "Here is your equation:\r<BR>\n" );
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document.write( "(x - 6) + x + 3x = 94\r<BR>\n" );
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document.write( "Can you finish now?\r<BR>\n" );
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document.write( "nycfunction@yahoo.com<BR>\n" );
document.write( "Guido\r<BR>\n" );
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