document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=276736>Question 276736</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Doreen and Irene plan to leave their houses at the same time and roller blade towards each other to meet for lunch after 4 hours on the road. Doreen can maintain a speed of 7 miles per hour which is 70% of Irenes speed. If they meet as planned what is the distance between houses? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #201636 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley77><B>checkley77(12844)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley77><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=201636\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> D=RT<BR>\n" );
document.write( "7 MPH IS DOREEN'S SPEED.<BR>\n" );
document.write( "7=.7X<BR>\n" );
document.write( "X=7/.7<BR>\n" );
document.write( "X=10 MPH FOR IRENE'S SPEED.<BR>\n" );
document.write( "D=(7+10)4<BR>\n" );
document.write( "D=17*4<BR>\n" );
document.write( "D=68 MILES FROM HOUSES TO THE LUNCH PLACE. </SPAN>\n" );
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