document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=276744>Question 276744</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How many pounds of an alloy containing 60% copper must be melted with an alloy containing 20% copper to obtain 4 pounds of an alloy containing 35% copper? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #201628 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley77><B>checkley77(12844)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley77><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=201628\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> .60x+.20(4-x)=.35*4<BR>\n" );
document.write( ".60x+.8-.20x=1.4<BR>\n" );
document.write( ".40x=1.4-.8<BR>\n" );
document.write( ".40x=.6<BR>\n" );
document.write( "x=.6/.4<BR>\n" );
document.write( "x=1.5 pounds of 60% copper is needed.<BR>\n" );
document.write( "4-1.5=2.5 pounds of 20% copper is needed.<BR>\n" );
document.write( "Proof:<BR>\n" );
document.write( ".60*1.5+.20*2.5=.35*4<BR>\n" );
document.write( ".9+.5=1.4<BR>\n" );
document.write( "1.4=1.4 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );