document.write( "Question 276491: If 5 adults and 2 children work together, a job can be done in a day. If only 2 adults work, then 6 children must work in order to complete the job in a day. The number of days that it takes for a child to do the job alone is:\r
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document.write( "a 9 b 25/3 c 26/3 d 8 e none of above \n" );
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Algebra.Com's Answer #201625 by ankor@dixie-net.com(22740) You can put this solution on YOUR website! If 5 adults and 2 children work together, a job can be done in a day. \n" ); document.write( "If only 2 adults work, then 6 children must work in order to complete the job in a day. \n" ); document.write( " The number of days that it takes for a child to do the job alone is: \n" ); document.write( ": \n" ); document.write( "Let a = time required when adult does the job alone \n" ); document.write( "let c = time required when a child does it \n" ); document.write( ": \n" ); document.write( "Let the completed job = 1 \n" ); document.write( ": \n" ); document.write( " \n" ); document.write( "and \n" ); document.write( " \n" ); document.write( ": \n" ); document.write( "Therefore: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "Cross multiply \n" ); document.write( "4a = 3c \n" ); document.write( "a = \n" ); document.write( "a = .75c \n" ); document.write( ": \n" ); document.write( "Using the 1st equation replace a with .75c, find c \n" ); document.write( " \n" ); document.write( "Multiply equation by 3c, results \n" ); document.write( "4(5) + 3(2) = 3c \n" ); document.write( "20 + 6 = 3c \n" ); document.write( "c = \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |