document.write( "Question 276721: \"x%5E3%2Bx%5E2-10x-6\"/x-3\r
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Algebra.Com's Answer #201622 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
In order to simplify this, we can use polynomial long division.\r
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\n" ); document.write( "\n" ); document.write( "So the quotient is \"x%5E2%2B4x%2B2\" and the remainder is 0. This means that \"%28x%5E3%2Bx%5E2-10x-6%29%2F%28x-3%29=x%5E2%2B4x%2B2%2B0%2F%28x-3%29\" or more simply \"%28x%5E3%2Bx%5E2-10x-6%29%2F%28x-3%29=x%5E2%2B4x%2B2\"\r
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\n" ); document.write( "\n" ); document.write( "Note: consequently, this means that \"x%5E3%2Bx%5E2-10x-6=%28x-3%29%28x%5E2%2B4x%2B2%29\" (just multiply both sides by \"x-3\")
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