document.write( "Question 276663: Given a square, construct another square whose area will be 5 times the area of the original square. Make a sketch and describe the construction step by step. Hint: Use Pyth. Thrm. to obtain the side of the new square. \n" ); document.write( "
Algebra.Com's Answer #201600 by josmiceli(19441)\"\" \"About 
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If the sides of the 1st square are \"x\", then
\n" ); document.write( "\"A%5B1%5D+=+x%5E2\"
\n" ); document.write( "I want the second square to have \"5\" times this area, so
\n" ); document.write( "\"A%5B2%5D+=+5A%5B1%5D\"
\n" ); document.write( "\"A%5B2%5D+=+5x%5E2\" or
\n" ); document.write( "\"A%5B2%5D+=+%28sqrt%285%29%2Ax%29%5E2\"
\n" ); document.write( "So, each side of the 2nd square is \"sqrt%285%29%2Ax\"
\n" ); document.write( "To construct this, you need some way of drawing a line
\n" ); document.write( "that has length = \"sqrt%285%29%2Ax\"
\n" ); document.write( "One way to do it is to draw a line that is the same length
\n" ); document.write( "as \"x\". Then draw a line perpendicular to it of length \"2x\"
\n" ); document.write( "Then draw the hypotenuse of this right triangle. By pythagorean
\n" ); document.write( "theorem, \"x%5E2+%2B+%282x%29%5E2+=+h%5E2\"
\n" ); document.write( "\"h%5E2+=+5x%5E2\"
\n" ); document.write( "\"h+=+sqrt%285%29x\"
\n" ); document.write( "Now construct a square with sides = \"h\"
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