document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=276636>Question 276636</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A man is 5 times as old as his son. In 5 years he will be nly 3 times as old as his son. Find the present age of each </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #201584 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=201584\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A man is 5 times as old as his son. In 5 years he will be nly 3 times as old as his son. Find the present age of each<BR>\n" );
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document.write( "Equations:<BR>\n" );
document.write( "F = 5S<BR>\n" );
document.write( "(F+5) = 3(S+5)<BR>\n" );
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document.write( "Substitute for \"F\" and solve for \"S\":<BR>\n" );
document.write( "(5S + 5) = 3S + 15<BR>\n" );
document.write( "2S = 10<BR>\n" );
document.write( "S = 5 yrs old (Son's age now)<BR>\n" );
document.write( "----<BR>\n" );
document.write( "Since F = 5S, F = 25 yrs old (Father's age now)<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
document.write( "==================================================== </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );