document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=33731>Question 33731</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A boat travels 60 km downstream in the same time that it takes to go 36 km upstream.  The speed of the boat in still water is 12 km/h.  Find the speed of the stream and the time it took to travel 60 km downstream.  Could someone  help me with this problem?  Thank you. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #20155 by </B><A HREF=/tutors/aboutme.mpl?userid=Paul><B>Paul(988)</B></A><img src=\"/images/stars/stars-11.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Paul><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=20155\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let the speed of the stream be x<BR>\n" );
document.write( "Equation:<BR>\n" );
document.write( "Upstream -->12+x Downstream -->12-x<BR>\n" );
document.write( "Equation:<BR>\n" );
document.write( "36(12+x)=60(12-x)<BR>\n" );
document.write( "432+36x=720-60x<BR>\n" );
document.write( "288=96x<BR>\n" );
document.write( "x=3<BR>\n" );
document.write( "Hence, the speed of the stream is 3mph.<BR>\n" );
document.write( "PAul.<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );