document.write( "Question 276593: I find this quite difficult, though I am gaining some level of understanding. I am unsure how to solve for the following 2 quadratic equations Please help
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document.write( "1. x2 – 2x – 13 = 0
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document.write( "2. 2x2 – 3x – 5 =0 \r
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document.write( "These are the steps I need to take, just unsure how\r
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document.write( "a. move the constant term to the right side of the equation
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document.write( "b. multiply each term in the equation by four times the cofficient of the x2 term
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document.write( "c. square the coefficient of the original x term and add it to both sides of the equation
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document.write( "d. take the square root of both sides
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document.write( "e. set the left side of the equation equal to the positive square root of the number on the right side and solve for x
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document.write( "f. set the left side of the equation equal to the negative square root of the number on the right side of the equation and solve for x \n" );
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Algebra.Com's Answer #201547 by richwmiller(17219)![]() ![]() You can put this solution on YOUR website!
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\n" ); document.write( "\n" ); document.write( "also \n" ); document.write( "(x+1)* (2x-5) = 0 \n" ); document.write( " |