document.write( "Question 276583: The length of a rectangle is 15 feet more than twice its width, and the perimeter is 120 feet. What are the length and width?\r
\n" ); document.write( "\n" ); document.write( "Two angles are supplementary. One of the angles is 32 degrees less thatn the measure of the other angle. What are the measures of the two angles?
\n" ); document.write( "

Algebra.Com's Answer #201537 by EMStelley(208)\"\" \"About 
You can put this solution on YOUR website!
I will answer your first question. If you have more than one, you should post them separately.\r
\n" ); document.write( "\n" ); document.write( "If we call the length L and the width W, then remember that perimeter is:
\n" ); document.write( "\"P=2L%2B2W\"
\n" ); document.write( "We have that the length is 15 more than twice the width, so we can represent length by 2W+15. Thus we have:\r
\n" ); document.write( "\n" ); document.write( "\"120=2%282W%2B15%29%2B2W\"
\n" ); document.write( "\"120=4W%2B30%2B2W\"
\n" ); document.write( "\"120=6W%2B30\"
\n" ); document.write( "\"90=6W\"
\n" ); document.write( "\"15=W\"\r
\n" ); document.write( "\n" ); document.write( "So the width is 15 feet. Thus the length would be 2(15)+15=45 feet.
\n" ); document.write( "
\n" );