document.write( "Question 276567: A rectangle has an area of 144cm^2 and a perimeter of 68cm. What are the lengths of the sides? \n" ); document.write( "
Algebra.Com's Answer #201528 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! A rectangle has an area of 144cm^2 and a perimeter of 68cm. What are the lengths of the sides? \n" ); document.write( "------ \n" ); document.write( "Equations: \n" ); document.write( "LW = 144 \n" ); document.write( "2(L+W) = 68 \n" ); document.write( "----- \n" ); document.write( "LW = 144 \n" ); document.write( "L + W = 34 \n" ); document.write( "----- \n" ); document.write( "L = 34-W \n" ); document.write( "------- \n" ); document.write( "Substitute and solve for \"W\": \n" ); document.write( "(34-W)W = 144 \n" ); document.write( "-w^2 + 34w - 144 = 0 \n" ); document.write( "w^2 - 34w + 144 = 0 \n" ); document.write( "--- \n" ); document.write( "w = [34 +- sqrt(34^2 -4*144)]/2 \n" ); document.write( "---- \n" ); document.write( "w = [34 +- sqrt(580)]/2 \n" ); document.write( "Positive solution: \n" ); document.write( "w = (17 + sqrt(145)) \n" ); document.write( "W is appoximately 29.04 cm \n" ); document.write( "---- \n" ); document.write( "Since L + W = 34, L = 34-29.04 = 4.96 cm \n" ); document.write( "====================================================== \n" ); document.write( "Cheers, \n" ); document.write( "stan H. \n" ); document.write( " |