document.write( "Question 276559: find two numbers whose difference is 200, such that the larger number is 5 times the smaller. \n" ); document.write( "
Algebra.Com's Answer #201523 by richwmiller(17219)\"\" \"About 
You can put this solution on YOUR website!
x-y=200
\n" ); document.write( "x=5y
\n" ); document.write( "5y-y=200
\n" ); document.write( "4y=200
\n" ); document.write( "y=50
\n" ); document.write( "x=250\r
\n" ); document.write( "\n" ); document.write( "response:
\n" ); document.write( " thank-you for the help. although i don't understand how you got the answer to the problem. however, i really do appreciate the help\r
\n" ); document.write( "\n" ); document.write( "The problem says 2 numbers differ by 200
\n" ); document.write( "let x be one number and y be the other
\n" ); document.write( "x-y=200
\n" ); document.write( "Do you see how they differ by 200?
\n" ); document.write( "The problem also says that one number is 5 times the other number
\n" ); document.write( "so let x=5y
\n" ); document.write( "Do you see how x is 5 times y?
\n" ); document.write( "so substitute 5y for x in x-y=200
\n" ); document.write( "and we get
\n" ); document.write( "5y-y=200
\n" ); document.write( "4y=200
\n" ); document.write( "y=50\r
\n" ); document.write( "\n" ); document.write( "but we also know that\r
\n" ); document.write( "\n" ); document.write( "x=5y
\n" ); document.write( "x=5*50
\n" ); document.write( "x=250
\n" ); document.write( " \n" ); document.write( "
\n" );